180=7x^2+x

Solution for 180=7x^2+x equation:

180=7x^2+x

We move all terms to the left:

180-(7x^2+x)=0

We get rid of parentheses

-7x^2-x+180=0

We add all the numbers together, and all the variables

-7x^2-1x+180=0

a = -7; b = -1; c = +180;
Δ = b2-4ac
Δ = -12-4·(-7)·180
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-71}{2*-7}=\frac{-70}{-14}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+71}{2*-7}=\frac{72}{-14}
=-5+1/7
$